3.3.8 \(\int (d+e x)^m \log (c (a+b x)^p) \, dx\) [208]

Optimal. Leaf size=89 \[ \frac {b p (d+e x)^{2+m} \, _2F_1\left (1,2+m;3+m;\frac {b (d+e x)}{b d-a e}\right )}{e (b d-a e) (1+m) (2+m)}+\frac {(d+e x)^{1+m} \log \left (c (a+b x)^p\right )}{e (1+m)} \]

[Out]

b*p*(e*x+d)^(2+m)*hypergeom([1, 2+m],[3+m],b*(e*x+d)/(-a*e+b*d))/e/(-a*e+b*d)/(1+m)/(2+m)+(e*x+d)^(1+m)*ln(c*(
b*x+a)^p)/e/(1+m)

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Rubi [A]
time = 0.03, antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {2442, 70} \begin {gather*} \frac {(d+e x)^{m+1} \log \left (c (a+b x)^p\right )}{e (m+1)}+\frac {b p (d+e x)^{m+2} \, _2F_1\left (1,m+2;m+3;\frac {b (d+e x)}{b d-a e}\right )}{e (m+1) (m+2) (b d-a e)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(d + e*x)^m*Log[c*(a + b*x)^p],x]

[Out]

(b*p*(d + e*x)^(2 + m)*Hypergeometric2F1[1, 2 + m, 3 + m, (b*(d + e*x))/(b*d - a*e)])/(e*(b*d - a*e)*(1 + m)*(
2 + m)) + ((d + e*x)^(1 + m)*Log[c*(a + b*x)^p])/(e*(1 + m))

Rule 70

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(b*c - a*d)^n*((a + b*x)^(m + 1)/(b^(
n + 1)*(m + 1)))*Hypergeometric2F1[-n, m + 1, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m
}, x] && NeQ[b*c - a*d, 0] &&  !IntegerQ[m] && IntegerQ[n]

Rule 2442

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[(f + g*
x)^(q + 1)*((a + b*Log[c*(d + e*x)^n])/(g*(q + 1))), x] - Dist[b*e*(n/(g*(q + 1))), Int[(f + g*x)^(q + 1)/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*f - d*g, 0] && NeQ[q, -1]

Rubi steps

\begin {align*} \int (d+e x)^m \log \left (c (a+b x)^p\right ) \, dx &=\frac {(d+e x)^{1+m} \log \left (c (a+b x)^p\right )}{e (1+m)}-\frac {(b p) \int \frac {(d+e x)^{1+m}}{a+b x} \, dx}{e (1+m)}\\ &=\frac {b p (d+e x)^{2+m} \, _2F_1\left (1,2+m;3+m;\frac {b (d+e x)}{b d-a e}\right )}{e (b d-a e) (1+m) (2+m)}+\frac {(d+e x)^{1+m} \log \left (c (a+b x)^p\right )}{e (1+m)}\\ \end {align*}

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Mathematica [A]
time = 0.04, size = 77, normalized size = 0.87 \begin {gather*} \frac {(d+e x)^{1+m} \left (\frac {b p (d+e x) \, _2F_1\left (1,2+m;3+m;\frac {b (d+e x)}{b d-a e}\right )}{(b d-a e) (2+m)}+\log \left (c (a+b x)^p\right )\right )}{e (1+m)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x)^m*Log[c*(a + b*x)^p],x]

[Out]

((d + e*x)^(1 + m)*((b*p*(d + e*x)*Hypergeometric2F1[1, 2 + m, 3 + m, (b*(d + e*x))/(b*d - a*e)])/((b*d - a*e)
*(2 + m)) + Log[c*(a + b*x)^p]))/(e*(1 + m))

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Maple [F]
time = 0.21, size = 0, normalized size = 0.00 \[\int \left (e x +d \right )^{m} \ln \left (c \left (b x +a \right )^{p}\right )\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^m*ln(c*(b*x+a)^p),x)

[Out]

int((e*x+d)^m*ln(c*(b*x+a)^p),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^m*log(c*(b*x+a)^p),x, algorithm="maxima")

[Out]

(x*e + d)*e^(m*log(x*e + d) - 1)*log((b*x + a)^p)/(m + 1) + integrate((((m + 1)*log(c) - p)*b*x*e + a*(m + 1)*
e*log(c) - b*d*p)*(x*e + d)^m/(b*(m + 1)*x*e + a*(m + 1)*e), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^m*log(c*(b*x+a)^p),x, algorithm="fricas")

[Out]

integral((x*e + d)^m*log((b*x + a)^p*c), x)

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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: HeuristicGCDFailed} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**m*ln(c*(b*x+a)**p),x)

[Out]

Exception raised: HeuristicGCDFailed >> no luck

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^m*log(c*(b*x+a)^p),x, algorithm="giac")

[Out]

integrate((x*e + d)^m*log((b*x + a)^p*c), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \ln \left (c\,{\left (a+b\,x\right )}^p\right )\,{\left (d+e\,x\right )}^m \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(log(c*(a + b*x)^p)*(d + e*x)^m,x)

[Out]

int(log(c*(a + b*x)^p)*(d + e*x)^m, x)

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